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原帖由 <i>luhuanke</i> 于 2012-7-7 21:26 发表 <a href="http://bbs.macd.cn/redirect.php?goto=findpost&pid=26396169&ptid=2105984" target="_blank"><img src="http://bbs.macd.cn/images/common/back.gif" border="0" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor='hand'; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onclick="if(!this.resized) {return true;} else {window.open(this.src);}" onmousewheel="return imgzoom(this);" alt="" /></a><br />
无偿介绍一种方法,MACD和KDJ和阴量(阴K线)的组合<br />
<br />
首先给公式:<br />
KDJ: <br />
RSV:=(CLOSE-LLV(LOW,9))/(HHV(HIGH,9)-LLV(LOW,9))*100;<br />
K:=SMA(RSV,3,1);<br />
D:=SMA(K,3,1);<br />
J:=3*K-2*D;<br />
aa:j0 and ref(j,2) ... <br /> |
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